Can virtual functions be private in C++?
In C++, virtual functions can be private and can be overridden by the derived class. For example, the following program compiles and runs fine.
Output:
1) ptr is a pointer of Base type and points to a Derived class object. When ptr->fun() is called, fun() ofDerived is executed.
2) int main() is a friend of Base. If we remove this friendship, the program won’t compile (See this). We get compiler error.
Note that this behavior is totally different in Java. In Java, private methods are final by default and cannot be overridden (See this)
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
#include<iostream>using namespace std;class Derived;class Base {private: virtual void fun() { cout << "Base Fun"; }friend int main();};class Derived: public Base {public: void fun() { cout << "Derived Fun"; }};int main(){ Base *ptr = new Derived; ptr->fun(); return 0;} |
Derived Fun
There are few things to note in the above program.
1) ptr is a pointer of Base type and points to a Derived class object. When ptr->fun() is called, fun() ofDerived is executed.
2) int main() is a friend of Base. If we remove this friendship, the program won’t compile (See this). We get compiler error.
Note that this behavior is totally different in Java. In Java, private methods are final by default and cannot be overridden (See this)
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
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