Why is the size of an empty class not zero in C++?
Predict the output of following program?
Output:
Output:
Output:
Output (with GCC compiler. See this):
#include<iostream>using namespace std;class Empty {};int main(){ cout << sizeof(Empty); return 0;} |
1Size of an empty class is not zero. It is 1 byte generally. It is nonzero to ensure that the two different objects will have different addresses. See the following example.
#include<iostream>using namespace std;class Empty { };int main(){ Empty a, b; if (&a == &b) cout << "impossible " << endl; else cout << "Fine " << endl; return 0;} |
FineFor the same reason (different objects should have different addresses), “new” always returns pointers to distinct objects. See the following example.
#include<iostream>using namespace std;class Empty { };int main(){ Empty* p1 = new Empty; Empty* p2 = new Empty; if (p1 == p2) cout << "impossible " << endl; else cout << "Fine " << endl; return 0;} |
FineNow guess the output of following program (This is tricky)
#include<iostream>using namespace std;class Empty { };class Derived: Empty { int a; };int main(){ cout << sizeof(Derived); return 0;} |
4Note that the output is not greater than 4. There is an interesting rule that says that an empty base class need not be represented by a separate byte. So compilers are free to make optimization in case of empty base classes. As an excercise, try the following program on your compiler.
#include <iostream>using namespace std; class Empty{}; class Derived1 : public Empty{}; class Derived2 : virtual public Empty{}; class Derived3 : public Empty{ char c;}; class Derived4 : virtual public Empty{ char c;}; class Dummy{ char c;}; int main(){ cout << "sizeof(Empty) " << sizeof(Empty) << endl; cout << "sizeof(Derived1) " << sizeof(Derived1) << endl; cout << "sizeof(Derived2) " << sizeof(Derived2) << endl; cout << "sizeof(Derived3) " << sizeof(Derived3) << endl; cout << "sizeof(Derived4) " << sizeof(Derived4) << endl; cout << "sizeof(Dummy) " << sizeof(Dummy) << endl; return 0;} |
0 comments:
Post a Comment